1.If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319 = 

Sol: Given log 0.317=0.3332 and log 0.318=0.3364

Then

Log 0.319=log0.318+ (log0.318-log0.317)

=0.3396 

2.A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there?   

Sol: Given x= 2 kg Packs

y= 1 kg packs 

=> x + y = 150 .......... Eqn 1

=> 2x + y = 264 .......... Eqn 2

On solving these two equations

x = 114 

By using equation 1

114 + y = 150

=> y = 36

=>Number of 2 kg Packs = 114. 

3. My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed?

a) 6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00

Sol: (Hint: Every 1 deg longitude is equal to 4 minutes. If west to east add time else subtract time)

Ans: 8:00 

4. A Flight takes off at 2 A.M from northeast direction and travels for 11 hours to reach the destination, which is in northwest direction. Given the latitude and longitude of source and destination. Find the local time of destination when the flight reaches there?

Ans: 7 AM (or) 1 PM

5. A moves 3 kms east from his starting point. He then travels 5 kms north. From that point he moves 8 kms to the east. How far is A from his starting point?

Ans: 13 kms

6. Aeroplane is flying at a particular angle and latitude, after some time latitude is given. (8 hrs later), u r asked to find the local time of the place.

Ans:

7. An Aeroplane starts from A (SOME LATITUDE IS GIVEN ACCORDING TO PLACE).At 2 AM local time to B (SOME LATITUDE). Traveling time is 10 Hours. What is the local time of B when it reaches B? 

Ans:

8. A plane moves from 9°N40°E to 9°N40°W. If the plane starts at 10 am and takes 8 hours to reach the destination, find the local arrival time.

Sol: Since it is moving from east to west longitude we need to add both

Ie, 40+40=80

Multiply the ans by 4

=>80*4=320min

Convert this min to hours i.e., 5hrs 33min

It takes 8hrs totally. So 8-5hr 30 min=2hr 30min

So the ans is 10am+2hr 30 min

Ans: 12:30 it will reach 

9. The size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds. And response will be back to programmer in 20 milliseconds. How much time the program takes to get a response back to the programmer, after it is sent?

Sol: The time being taken to fill the bucket.

After reaching program it waits there for 10ms and back to the programmer in

20 ms. then total time to get the response is

20ms +10 ms=30ms 

Ans: 30ms 

10. A file is transferred from one location to another in ‘buckets’. The size of the bucket is 10 kilobytes. Eh bucket gets filled at the rate of 0.0001 kilobytes per millisecond. The transmission time from sender to receiver is 10 milliseconds per bucket. After the receipt of the bucket the receiver sends an acknowledgement that reaches sender in 100 milliseconds. Assuming no error during transmission, write a formula to calculate the time taken in seconds to successfully complete the transfer of a file of size N kilobytes.

Ans: (n/1000)*(n/10)*10+ (n/100).... (Not 100% sure)